Explore the solutions to quadratic equations and the behavior of polynomial functions of degree 2, including their graphical representations and variations.
Extract
[...] and increasing on ; + Here is its variation table: x g is a polynomial function of degree its graphical representation is therefore a parabola. a = so [...]
[...] This means that the solutions of the inequality are ;3.5] and curve is therefore 'above' curve C when x belongs to the interval ; 3.5]. Exercise 2 Solving = 0 is equivalent to solving: We calculate the discriminant so the equation has two distinct solutions: The solutions are is a degree 2 polynomial and a > then f is first decreases, then increases. The function f is therefore positive except between its roots. The function f is therefore positive on the intervals ] - ? ; and ; and negative on the interval ; 4]. [...]
