Combustion energy, calorific power, octane, palmitine, chemical reaction, energy storage, limiting reactant, exothermic reaction, bond energy
Reader
Abstract
Extract
of 6
Abstract
This document discusses the calculation of combustion energy and calorific power of octane and palmitine, including the energy stored by water and the limiting reactant in a chemical reaction.
Extract
[...] The reflux heating allows heating the mixture without loss of matter by evaporation. The reflux assembly consists of a condenser located above the balloon which allows the vapors to condense on its wall and fall back into the balloon. 2. Soda being very basic, its use requires body protection. We must therefore wear gloves to avoid splashes on the hands and body parts and protect our eyes with safety glasses. Wearing an apron or protective blouse would be a plus when handling to avoid splashes and burns in case of overturning. [...]
[...] Mass of Vol Octane = 703g.L-1 Quantity used of for 1km 5. :On the reactive side carbon atoms hydrogen atoms and 25 oxygen atoms. On the product side carbon atoms hydrogen atoms and 25 oxygen atoms, so the equality is respected. 6. For 1km we need of and according to the equation, we produce 8 times more for an octane molecule. Thus we form mole of . 7. According to we can get the mass as a function of n and M according 8. [...]
[...] The calorific power is the energy that can be recovered in the form of heat when one kilogram of fuel reacts completely with oxygen. During combustion we have calculated an energy loss . This magnitude corresponds to the energy released for 1 mole of , we need to convert it to 1kg in order to obtain the calorific power (in We know that so we can make a cross product: Thus The combustion energy being negative because there is a loss of energy from the system, the calorific power will therefore be positive because it corresponds to the recoverable energy. [...]
[...] Palmitine contains 51 carbon atoms oxygen atoms and 98 hydrogen atoms. 5. For 3.1g of palmitine we have 6. For 1g of sodium we have 7. According to the reaction equation, we need 3 times more soda than palmitin thus: Therefore, we have more soda than palmitin, so the excess reactant is soda. 8. On prefer water salt, we call this step of release. The salt being more soluble than soap molecules, we play on the solubility indices. 9. 10. [...]
